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Molarity Calculator | M = n/V

Calculate molarity, moles, or volume of solutions using M = n/V formula.

What Is the Molarity Calculator | M = n/V?

The Molarity Calculator solves for any variable in the fundamental concentration equation M = n/V, finding molarity from moles and volume, moles from concentration and volume, or volume from moles and concentration. A built-in dilution mode handles the lab workhorse equation C₁V₁ = C₂V₂ for preparing working solutions from stock concentrations.

  • Three-way solve: click which variable to find, molarity, moles, or volume, and enter the other two.
  • Unit flexibility: volume input accepts mL, L, or µL, no manual conversion needed.
  • Dilution mode: C₁V₁ = C₂V₂ with four-way solve for any of the four unknowns, plus dilution factor output.
  • Step-by-step working: every calculation shows the substitution and arithmetic so you can verify the result.

Formula

M = n / V
Molarity (mol/L) = moles of solute ÷ volume of solution in litres
FormulaRearrangementUse case
M = n / VMolarity from moles and volumeMaking a standard solution
n = M × VMoles from molarity and volumeFinding moles in a given volume
V = n / MVolume from moles and molarityFinding what volume to use
C₁V₁ = C₂V₂Dilution equation (moles conserved)Serial dilutions, lab prep
V₁ = C₂V₂ / C₁Volume to pipette from stockMaking working solutions

How to Use

  1. 1Select "Molarity M = n/V" for standard concentration problems, or "Dilution C₁V₁ = C₂V₂" for dilution problems.
  2. 2In basic mode: click the variable you want to solve for (M, n, or V).
  3. 3Enter the two known values in the fields that appear.
  4. 4For volume, choose the unit (mL, L, or µL) from the dropdown next to the label.
  5. 5Press Enter or click Calculate to compute the result.
  6. 6In dilution mode: click which variable to solve for and enter the other three values.
  7. 7Click Clear to reset all fields and start a new calculation.

Example Calculation

Example 1, Find molarity of a NaCl solution

Problem: 5.85 g NaCl dissolved in 250 mL of water. Molar mass of NaCl = 58.44 g/mol Step 1: Convert grams to moles n = 5.85 ÷ 58.44 = 0.1001 mol Step 2: Convert mL to L V = 250 mL = 0.250 L Step 3: Calculate molarity M = n / V = 0.1001 / 0.250 = 0.400 mol/L

Example 2, Dilution: make 100 mL of 0.5 M HCl from 2 M stock

C₁V₁ = C₂V₂ C₁ = 2 M (stock) C₂ = 0.5 M (target) V₂ = 100 mL V₁ = ? V₁ = (C₂ × V₂) / C₁ = (0.5 × 100) / 2 = 25 mL → Pipette 25 mL of 2 M HCl into a 100 mL volumetric flask, make up to the mark with distilled water.

Dilution factor

The dilution factor (DF) = C₁ / C₂ = V₂ / V₁. A 1:4 dilution (25 mL stock into 100 mL final) gives DF = 4, meaning the concentration is reduced to ¼ of the original. Always add concentrated solution to water, not water to concentrated acid.

Understanding Molarity | M = n/V

What Is Molarity?

Molarity (symbol M) is the most widely used measure of solution concentration in chemistry. It is defined as the number of moles of solute dissolved in exactly one litre of solution, not solvent. The unit is mol/L, commonly written as M (molar). A 1.0 M NaCl solution contains 1.0 mole of sodium chloride in every litre of the final solution.

Molarity is preferred over mass-based concentrations (like percent by mass) because it directly counts molecules, which is what matters in chemical reactions. The stoichiometry of a reaction is always expressed in moles, so working in molarity allows direct conversion from volume to moles without knowing the density of the solution.

  • Molarity is temperature-dependent, volume changes with temperature, so M changes slightly.
  • Molality (mol/kg solvent) is temperature-independent and used for colligative property calculations.
  • At low concentrations (dilute solutions), molarity ≈ molality numerically.
  • Standard solutions are often prepared at exactly 25°C to ensure precise volume.

The Dilution Equation C₁V₁ = C₂V₂

When you dilute a solution, you add more solvent but the number of moles of solute stays constant. This conservation of moles gives the dilution equation: C₁V₁ = C₂V₂, where C₁ and V₁ are the initial concentration and volume, and C₂ and V₂ are the final values. This equation can be solved for any of the four variables by simple rearrangement.

The dilution factor (DF) describes how much the concentration has been reduced: DF = C₁/C₂ = V₂/V₁. A 1:10 dilution means 1 part stock in 10 parts final solution, giving DF = 10. Serial dilutions (repeated 1:10 dilutions) are commonly used in microbiology for bacterial counts and in ELISA assays for antibody titrations.

  • Both concentrations must be in the same units (both mol/L, or both mg/mL, etc.).
  • Both volumes must be in the same units (both mL, or both L).
  • C₁V₁ = C₂V₂ works for any concentration unit, molar, mass/volume, percent.
  • For serial dilutions, apply the equation repeatedly: first dilution output becomes the next input.

Concentration Units in Chemistry

While molarity (mol/L) is the standard in most lab contexts, other concentration units are used for specific applications:

  • Molality (m): mol solute / kg solvent. Used for boiling point elevation and freezing point depression calculations. Temperature-independent.
  • Normality (N): equivalents of solute per litre. Used in acid-base and redox titrations. 1 M H₂SO₄ = 2 N (two protons per molecule).
  • Mass percent (% w/w): grams solute per 100 g solution. Common for concentrated commercial reagents (e.g. 37% HCl).
  • ppm / ppb: µg/mL (ppm) and ng/mL (ppb), used for trace analytes in environmental and clinical chemistry.

Preparing Solutions in the Lab

The correct procedure for preparing a solution of known molarity is critical for reproducibility. Always add solute to less than the target volume of solvent, dissolve completely, then transfer to a volumetric flask and make up to exactly the target volume. Never add the target volume of water directly to a mass of solute in a beaker, the final volume will be slightly off due to volume of mixing.

  • Use a calibrated volumetric flask, not a beaker or Erlenmeyer, for accurate volume.
  • For concentrated acids: add acid slowly to water, never water to acid (exothermic).
  • Check solution density if preparing from a concentrated reagent (e.g. 37% HCl): use ρ × %purity ÷ M_r.
  • Allow the solution to equilibrate to the reference temperature before making up to volume.

Frequently Asked Questions

What is molarity and how is it defined?

Molarity (M) is the number of moles of solute per litre of solution: M = n/V. A 1 M solution contains 1 mole of solute in each litre of the final solution.

Important: molarity is calculated based on the total volume of the solution, not the volume of solvent added. When 58.44 g of NaCl (1 mol) is dissolved in water and made up to 1.000 L, the result is a 1.000 M NaCl solution.

How do I calculate molarity from grams?

First convert grams to moles using the molar mass, then divide by volume in litres:

moles = mass (g) ÷ molar mass (g/mol) M = moles ÷ volume (L) Example: 9.0 g of glucose (M_r = 180.16 g/mol) in 500 mL: moles = 9.0 / 180.16 = 0.04995 mol M = 0.04995 / 0.500 = 0.0999 mol/L ≈ 0.1 M

What is the dilution equation and when do I use it?

The dilution equation C₁V₁ = C₂V₂ states that moles of solute are conserved during dilution. Use it whenever you need to prepare a less concentrated working solution from a more concentrated stock solution.

  • C₁ = stock concentration, V₁ = volume of stock to take
  • C₂ = target concentration, V₂ = final volume of diluted solution
  • Solve for the unknown variable by rearranging the equation
  • Works with any concentration unit as long as C₁ and C₂ are in the same units

What is the difference between molarity and molality?

Molarity (M) = moles of solute / litres of solution. Molality (m) = moles of solute / kilograms of solvent. The key differences:

  • Molarity depends on temperature (volume changes); molality does not.
  • Molality is used for colligative properties: boiling point elevation, freezing point depression, osmotic pressure.
  • At low concentrations in water, M ≈ m numerically (since 1 L water ≈ 1 kg).
  • Most lab work uses molarity; physical chemistry and thermodynamics often use molality.

How do I prepare a 1 M solution of NaOH?

To prepare 1 L of 1 M NaOH (molar mass = 39.997 g/mol):

  • Weigh 39.997 g of NaOH pellets (or ~ 40.0 g)
  • Add to a 1 L volumetric flask with ~ 500 mL of distilled water
  • Swirl to dissolve completely (NaOH is exothermic, the solution will heat up)
  • Allow to cool to room temperature
  • Add distilled water until the meniscus reaches exactly the 1 L mark
  • Stopper and invert several times to mix thoroughly

How does molarity relate to normality?

Normality (N) = Molarity × n-factor, where n-factor is the number of equivalents per mole. For acids, n-factor = number of replaceable H⁺ ions; for bases, number of OH⁻ ions; for redox, change in oxidation state.

  • HCl: 1 M = 1 N (one H⁺ per molecule)
  • H₂SO₄: 1 M = 2 N (two H⁺ per molecule)
  • H₃PO₄: 1 M = 3 N (three replaceable H⁺)
  • Normality is used in titration calculations: N₁V₁ = N₂V₂ at the equivalence point

What volume units does the calculator accept?

The calculator accepts three volume units via the dropdown selector:

  • mL (millilitres), most common in lab work
  • L (litres), for larger volumes
  • µL (microlitres), for microplate and PCR applications

The conversion is handled automatically: 1 L = 1000 mL = 1,000,000 µL. Select the unit that matches your measurement and enter the numerical value without converting.

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